Page 21 - PSE M1 BOOSTER

POWER GENERATION USING PETROL

Before spray: After spray:

Time of Running: 17.22 Min Time of Running: 22.08 Min

Fuel consumed: 100 ml Fuel consumed: 100 ml

Power output: Power output:

P=V*I P=V*I

200P = 230V*I 200P = 230V*I
I=0.87 A I=0.87 A

Hr= 0.287 Hrs Hr= 0.368 Hrs

Watt hour = P*Hr Watt hour = P*Hr

= 200* 0.287 = 200* 0.368
= 57.4 Watthr = 73.6 Watthr

For 1 Ltr = 574 Watt hour For 1 Ltr = 736 Watt hour

(i.e) 0.574 KwHr for one litre of petrol. (i.e) 0.736 KwHr for one litre of Petrol.

Improvement = [after Kw Hr - before Kw Hr]
= [0.736 - 0.574]

= 0.162 Therefore, we find that 28% output power has been increased.